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Showing posts with label Mechanics. Show all posts
Showing posts with label Mechanics. Show all posts

Saturday, October 18, 2014

Rate, Distance, and Time Problems, 7

Category: Physics, Mechanics

"Published in Newark, California, USA"


A motorist has to travel 3.50 km in a city where his average speed should not exceed 25 km/hr. If he increases his average speed to 40 km/hr, how much time will he gain in his journey?

Solution:

The given problem is about rate, distance, and time problem in which the average speed is increased. Let's assume that the distance for the two cases is the same which is 3.50 km. 

If the speed limit in a city is 25 km/hr, then his travel time is





If he increased his speed to 40 km/hr, then his travel time is
 
 
 
 

Therefore, his travel time will gain by
 
 
 
                         or
 


Friday, October 10, 2014

Inclined Plane Problems, 3

Category: Mechanics, Physics

"Published in Newark, California, USA"

The block shown in the figure is acted on by its weight W = 400 lbs., a horizontal force F = 600 lbs., and the pressure P exerted by the inclined plane. The resultant R of these forces is parallel to the incline. Determine P and R. Does the block move up or down the incline?

Photo by Math Principles in Everyday Life

Solution:

The first thing that we need to do is to get the x and y components of each forces and then isolate the given figure as follows 

Photo by Math Principles in Everyday Life

Since we don't know the direction of the resultant, let's assume that the direction is upward because the value of F is greater than the weight of a block. 

The sum of x component is






The sum of y component is









Substitute the value of P to the first equation. Therefore, the value of R is





Since the value of R is positive, then the block is moving upward the incline. 
 

Thursday, October 9, 2014

Resultant of Forces and Components, 2

Category: Mechanics, Physics

"Published in Newark, California, USA"

The force system as shown in the figure has a resultant of 200 lbs. pointing up along the y axis. Compute the values of F and θ required to give this resultant.

Photo by Math Principles in Everyday Life

Solution:

The first thing that we need to do is to get the x and y components of each forces and then isolate the given figure as follows

Photo by Math Principles in Everyday Life

The sum of y components is






The sum of x components is


 
 
 
 

Divide the first equation by the second equation in order to solve for θ, we have
 


Take the inverse tangent on both sides on the equation, we have



                                or

Substitute the value of θ to either of the two working equations, we have