Category: Algebra
"Published in Newark, California, USA"
Lilian's average in 3 quizzes is 80%. If she made 5% more in the first than in the second and 8% less in the third, what grades did she get in the three quizzes?
Solution:
The given item in a word problem is the average of the three quizzes of Lilian with conditions of her quizzes and we have to find the grades of her quizzes as follows
Let x = the score of her 2nd quiz
x + 5% = the score of her 1st quiz
x - 8% = the score of her 3rd quiz
Average of three quizzes = ⅓(1st Quiz + 2nd Quiz + 3rd Quiz)
80% = ⅓ (x + 5% + x + x - 8%)
3x - 3% = 240%
3x = 240% + 3%
3x = 243%
x = 81%
Therefore
Lilian's grade in 1st Quiz = x + 5% = 81% + 5% = 86%
Lilian's grade in 2nd Quiz = x = 81%
Lilian's grade in 3rd Quiz = x - 8% = 81% - 8% = 73%

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Sunday, 27 January 2013
Saturday, 26 January 2013
First Order Linear Equation, 2
Category: Differential Equations, Trigonometry, Integral Calculus
"Published in Newark, California, USA"
Find the particular solution for
when
Solution:
Consider the given equation
If
then
If
then
Since
then the given equation is not an Exact Equation. We need to find the integrating factor first and then multiply it on both sides of an equation so that the given equation becomes an Exact Equation.
Consider again the given equation
Arrange the above equation into its standard form as follows
where
and
The integrating factor is
The general solution for the above equation is
If
then
Therefore, the particular solution for the above equation is
We can consider the above equation as a final answer but if you want to further simplify the above equation, consider the Half Angle Formula as follows
Hence, the above equation becomes
"Published in Newark, California, USA"
Find the particular solution for
when
Solution:
Consider the given equation
If
then
If
then
Since
then the given equation is not an Exact Equation. We need to find the integrating factor first and then multiply it on both sides of an equation so that the given equation becomes an Exact Equation.
Consider again the given equation
Arrange the above equation into its standard form as follows
where
and
The integrating factor is
The general solution for the above equation is
If
then
Therefore, the particular solution for the above equation is
We can consider the above equation as a final answer but if you want to further simplify the above equation, consider the Half Angle Formula as follows
Hence, the above equation becomes
Friday, 25 January 2013
More Integration Procedures
Category: Integral Calculus, Trigonometry
"Published in Newark, California, USA"
Evaluate
Solution:
Since there's a double angle involved in the integration, we have to convert it into it's equivalent single angle as follows
Consider
Consider
Consider
Therefore
"Published in Newark, California, USA"
Evaluate
Solution:
Since there's a double angle involved in the integration, we have to convert it into it's equivalent single angle as follows
Consider
Consider
Consider
Therefore
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