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вторник, 28 мая 2013 г.

More Integration Procedures, 8

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate

Solution:

Consider the given equation above


Convert each term into their equivalent exponential power, we have


All terms can be integrated by integration of powers




Substitute the value of limits and therefore, the answer is













понедельник, 27 мая 2013 г.

Partial Differentiation

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

If

show that



Solution:

Consider the given equation above



Take the partial derivative with respect to x, consider y as a constant, we have











Consider the given equation above again



Take the partial derivative with respect to y, consider x as a constant, we have











If
then







Therefore,



воскресенье, 26 мая 2013 г.

Differentiation - First Derivative

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

Find y' for the given value of x for


Solution:

Consider the given equation above




Simplify the numerator in order to avoid the confusion later for differentiation, we have








Take the derivative of the above equation with respect to x









If x = 1, then the value of y' is equal to