"Published in Newark, California, USA"
Solve the following systems by substitution:
Solution:
Consider the given equations above
The first equation can be factored by the sum of the two cubes as follows
But

Hence, the above equation becomes
Substitute the value of y to the above equation, we have
By using completing the square method, the value of x is
If

If

Since the solutions of the two equations have imaginary numbers or complex numbers, then the two equations have no solution.