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Friday, January 31, 2014

Finding Equation - Circle, 9

Category: Analytic Geometry, Plane Geometry, Algebra

"Published in Fremont, California, USA"

Find the equation of a circle whose center on the line 8x + 5y = 8 and passes through the points (2, 1) and (3, 5).

Solution:

To illustrate the problem, it is better to draw the figure as follows

The center of a circle is located along the line 8x + 5y = 8 and passes through the points (3, 5) and (2, 1). (Photo by Math Principles in Everyday Life) 



 

To get the radius of a circle, we need to use the distance of two points formula as follows










Next, we need another equation which is 8x + 5y = 8 in order to solve for x and y which is the coordinates of the center of a circle. Multiply equation (1) by 4, we have


Subtract the above equation from the equation of a line, we have



Substitute the value of y to the equation of a line in order to get the value of x, we have






Hence, the center of a circle is C (-3/2, 4). The radius of a circle is









Therefore, the equation of a circle is






Thursday, January 30, 2014

Finding Equation - Circle, 8

Category: Analytic Geometry, Plane Geometry, Algebra

"Published in Newark, California, USA"

Find the equation of a circle which is tangent to the y-axis and passes through the points (1, 5) and (8, -2).

Solution:

To illustrate the problem, it is better to draw the figure as follows

A circle is tangent to the y-axis and passes thru (1, 5) and (8, -2). (Photo by Math Principles in Everyday Life)

Since the given circle is tangent to the y-axis, then the radius is equal to h which is the x-coordinate of the center of a circle. 

Since the two points of a circle are given, then we can use the distance of two points formula in order to get the radius of a circle as follows









We need to get another equation because the above equation consists of two variables as follows







Substitute the value of h from equation (1) to equation (2), we have






After equating each factor to zero, the values of k are 10 and 2.

If k = 10, then




Hence, the center of a circle is C (13, 10) and its radius is r = h = 13.

Therefore, the equation of a circle is





If k = 2, then




Hence, the center of a circle is C (5, 2) and its radius is r = h = 5.

Therefore, the equation of a circle is