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Showing posts with label Analytic Geometry. Show all posts
Showing posts with label Analytic Geometry. Show all posts

Tuesday, November 25, 2014

Sketching the Graph of a Polynomial, 5

Category: Analytic Geometry

"Published in Vacaville, California, USA"

Sketch the graph of a polynomial:


Solution:

Consider the given equation above 


Since the given equation, is already factored, then we can get the x-intercept by setting y = 0. The x-intercept is 1.

If we set x = 0, the y-intercept of the given equation is   




Since we now the x-intercept, then we can sketch the location or direction of a curve as follows  

If x < 0, then y = (+)⁵ = (+)
If 0 < x < 1, then y = (+)⁵ = (+)
If x > 1, then y = (-)⁵ = (-)

Here's the graph of a polynomial:  

Photo by Math Principles in Everyday Life

Monday, November 24, 2014

Sketching the Graph of a Polynomial, 4

Category: Analytic Geometry

"Published in Vacaville, California, USA"

Sketch the graph of a polynomial:


Solution:

Consider the given equation above  


Since the given equation, is already factored, then we can get the x-intercepts by setting y = 0. The x-intercepts are -1 and 3.   

If we set x = 0, the y-intercept of the given equation is  




Since we now the x-intercepts, then we can sketch the location or direction of a curve as follows 

If x < -1, then y = ¼ (-)³(-) = (+)
If -1 < x < 0, then y =  ¼ (+)³(-) = (-)
If 0 < x < 3, then y = ¼ (+)³(-) = (-)
If x > 3, then y = ¼ (+)³(+) = (+) 

Here's the graph of a polynomial: 

Photo by Math Principles in Everyday Life

Sunday, November 23, 2014

Sketching the Graph of a Polynomial, 3

Category: Analytic Geometry

"Published in Vacaville, California, USA

Sketch the graph of a polynomial:


Solution:

Consider the given equation above 


Since the given equation, is already factored, then we can get the x-intercepts by setting y = 0. The x-intercepts are 1 and 3.  

If we set x = 0, the y-intercept of the given equation is 




Since we now the x-intercepts, then we can sketch the location or direction of a curve as follows

If x < 0, then y = (-)²(-) = (-)
If 0 < x < 1, then y = (-)²(-) = (-)
If 1 < x < 3, then y = (+)²(-) = (-)
If x > 3, then y = (+)²(+) = (+)

Here's the graph of a polynomial:

Photo by Math Principles in Everyday Life

Saturday, November 22, 2014

Sketching the Graph of a Polynomial, 2

Category: Analytic Geometry

"Published in Vacaville, California, USA"

Sketch the graph of a polynomial:


Solution:

Consider the given equation above


Since the given equation, is already factored, then we can get the x-intercepts by setting y = 0. The x-intercepts are 1, -1, and 2. 

If we set x = 0, the y-intercept of the given equation is


 

Since we now the x-intercepts, then we can sketch the location or direction of a curve as follows

If x < -1, then y = (-)(-)(-) = (-)
If -1 < x < 0, then y = (-)(+)(-) = (+)
If 0 < x < 1, then y = (-)(+)(-) = (+)
If 1 < x < 2, then y = (+)(+)(-) = (-)
If x > 2, then y = (+)(+)(+) = (+)

Here's the graph of a polynomial:
 
Photo by Math Principles in Everyday Life

Thursday, November 13, 2014

Rotation of a Parabola, 2

Category: Analytic Geometry

"Published in Newark, California, USA"

Given the equation of a parabola


Find the new equation of a parabola if the given parabola is rotated counterclockwise about the origin at

Solution:

To illustrate the given problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

Since the given angle of rotation is written as inverse tangent function, then we can get the sine and cosine of the given angle of rotation by using basic trigonometric functions of a right triangle. 


 
Photo by Math Principles in Everyday Life

If the given equation is written in rectangular coordinate system, then we need to convert it into polar coordinate system as follows  

  



Next, substitute θ with θ - Ï• and then expand using the sum and difference of two angles formula, we have 







    
Convert the above equation into rectangular coordinate system in order to get its final equation. Therefore, the new equation of a parabola is 







Note: If the axes of any conic sections are not parallel to x and y axes, then the equation of any conic sections has xy term which is the general equation of any conic sections like parabola, ellipse, and hyperbola. Circle has no xy term always in any cases.

Wednesday, November 12, 2014

Rotation of a Parabola

Category: Analytic Geometry

"Published in Vacaville, California, USA"

Given the equation of a parabola


Find the new equation of a parabola if the given parabola is rotated counterclockwise about the origin at 90°.  

Solution:

To illustrate the given problem, it is better to draw the figure as follows   

Photo by Math Principles in Everyday Life

If the given equation is written in rectangular coordinate system, then we need to convert it into polar coordinate system as follows   



Next, substitute θ with θ - 90° and then expand using the sum and difference of two angles formula, we have  








Convert the above equation into rectangular coordinate system in order to get its final equation. Therefore, the new equation of a parabola is