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Sunday, August 17, 2014

Triangular Prism Problems, 4

Category: Solid Geometry

"Published in Vacaville, California, USA"

The trough shown in the figure has triangular ends which lie in parallel planes. The top of the trough is a horizontal rectangle 20 in. by 33 in., and the depth of the trough is 16 in. 

(a) How many gallons of water will it hold? (One gal. = 231 cu. in.)
(b) How many gallons does it contain when the depth of the water is 10 in.?
(c) What is the depth of the water when the trough contains 3 gals.?
(d) Find the wetted surface when the depth of the water is 9 in.

Photo by Math Principles in Everyday Life

Solution:

(a) Consider the given figure above

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The area of the base is




Therefore, the volume of a trough when filled with water which is the volume of a prism is




The volume of a trough in gallons is





(b) Consider the front side of a trough


Photo by Math Principles in Everyday Life

Bu using similar triangles, the area of the base with water is











Therefore, the volume of a trough with water is







The volume of a trough with water in gallons is







(c) The volume of a trough with water in cubic inches is







The area of the base of a trough with water is







By using similar triangles

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Therefore, the depth of water in a trough is













(d) Consider the front side of a trough


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By using similar triangles, the length of the base is







Let's assume that the base of a trough is an isosceles triangle.

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By using Pythagorean Theorem, the length of the wetted edge is














The area of the wetted base of a trough is




The lateral area of the wetted surface of a trough is





Therefore, the total area of the wetted surface of a trough is








Saturday, August 16, 2014

More Prism Problems, 2

Category: Solid Geometry

"Published in Newark, California, USA"

A railway cut 200 ft. and 30 ft. wide at the bottom is made with sloping sides, which are 80 ft. and 60 ft. in length. The 80 ft. side is inclined 45° and and the other side is inclined 30° to the horizontal. Find the cost of removing the earth at $2 per load, if the trucks have a capacity of 4 cu. yd.

Photo by Math Principles in Everyday Life

Solution:

Consider the given figure above

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To understand more the problem, it is better to analyze the front side which is a quadrilateral and the base of the prism, and then label further as follows

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If you draw vertical lines from the two upper vertices and horizontal lines from the two lower vertices of a quadrilateral, then it becomes a trapezoid. Since the sides and angles of a quadrilateral are given, then we can solve the remaining sides of two right triangles.
 
Photo by Math Principles in Everyday Life

The area of a trapezoid is



 




The area of 45° right triangle is





The area of 30° right triangle is





The area of a quadrilateral which is the base of a prism is





The volume of the earth removed from a railway cut which is the volume of a prism is


 
   
The volume of a prism in cubic yards is
 
 
 
 
   
Therefore, the cost of removing the earth from a railway cut is