Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
Since the two terms have both even exponents, then we can factor the given equation by the sum and difference of two squares as follows
Factor each group by the sum and difference of two cubes as follows
Therefore, the factors are
Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
If you will examine the given equation, each terms are perfect cube. (a + b) is considered as a single variable. The given equation can be factored by the sum and difference of two cubes. Therefore, the factors are
Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
If you will examine the equation above, there's a common factor which is a. Take out their common factor as follows
Since each terms in the parenthesis are perfect cube, then we can factor the grouped terms as the sum and difference of two cubes. Therefore, the factors are
