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Wednesday, April 24, 2013

Inspecting Integrating Factors

Category: Differential Equations, Integral Calculus, Algebra

"Published in Newark, California, USA"

Find the general solution for



Solution:

Consider the given equation above



Expand the above equation and regroup as follows





Divide both sides of the equation by y2, we have



The grouped terms in parenthesis can be simplified as an exact differential as follows



Integrate on both sides of the equation, we have





Multiply both sides of the equation by y, we have



Therefore, the final answer is