"Published in Newark, California, USA"
Determine the value of a 3-digit number if the unit's digit is 5 more than the hundred's digit and the ten's digit is one more than twice the hundred's digit if the sum of the digits is 2 more than twice the unit's digit.
Solution:
The given word problem above is about getting the value of a three digit number with given conditions for each digit. Let's analyze the given word problem as follows:
Let x = be the value of hundred's digit
x + 5 = be the value of unit's digit
2x + 1 = be the value of ten's digit
If the given word problem says ".....if the sum of the digits is 2 more than twice the unit's digit." then the working equation will be
Solve for the value of x. This will be the value of hundred's digit.
The value of hundred's digit = x = 3
The value of unit's digit = x + 5 = 3 + 5 = 8
The value of ten's digit = 2x + 1 = 2(3) + 1 = 6 + 1 = 7
Therefore, the value of a three digit number is 378.