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Sunday, January 27, 2013

Word Problem - Average Problem

Category: Algebra

"Published in Newark, California, USA"

Lilian's average in 3 quizzes is 80%. If she made 5% more in the first than in the second and 8% less in the third, what grades did she get in the three quizzes?

Solution:

The given item in a word problem is the average of the three quizzes of Lilian with conditions of her quizzes and we have to find the grades of her quizzes as follows

Let    x = the score of her 2nd quiz
        x + 5% = the score of her 1st quiz
        x - 8% = the score of her 3rd quiz

            Average of three quizzes = ⅓(1st Quiz + 2nd Quiz + 3rd Quiz)

                          80% = ⅓ (x + 5% + x + x - 8%)

                                   3x - 3% = 240%

                                           3x = 240% + 3%

                                           3x = 243%

                                             x = 81%

Therefore

Lilian's grade in 1st Quiz = x + 5% = 81% + 5% = 86%

Lilian's grade in 2nd Quiz = x = 81%

Lilian's grade in 3rd Quiz = x - 8% = 81% - 8% = 73%


Saturday, January 26, 2013

First Order Linear Equation, 2

Category: Differential Equations, Trigonometry, Integral Calculus

"Published in Newark, California, USA"

Find the particular solution for


when

Solution:

Consider the given equation 





If 
then

If
then

Since

then the given equation is not an Exact Equation. We need to find the integrating factor first and then multiply it on both sides of an equation so that the given equation becomes an Exact Equation. 

Consider again the given equation



Arrange the above equation into its standard form as follows









where
and

The integrating factor is







The general solution for the above equation is 













If
then







Therefore, the particular solution for the above equation is 





We can consider the above equation as a final answer but if you want to further simplify the above equation, consider the Half Angle Formula as follows







Hence, the above equation becomes








Friday, January 25, 2013

More Integration Procedures

Category: Integral Calculus, Trigonometry

"Published in Newark, California, USA"

Evaluate

Solution:

Since there's a double angle involved in the integration, we have to convert it into it's equivalent single angle as follows

















Consider











Consider









Consider











Therefore