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Thursday, April 30, 2015

Dalton's Law of Partial Pressure

Category: Chemical Engineering Math

"Published in Newark, California, USA"

How many grams of KClO3 are needed to prepare 1.8 L of O2 gas that is collected over H2O at 22°C and 760 torr? Vapor pressure of water at 22°C is 19.8 torr.

Solution:

From the given word problem, it is about Dalton's Law of Partial Pressure because it involves the mixture of gas vapors. In this problem, oxygen gas that is collected from the decomposition of KClO3 over water is not a pure oxygen. It is a mixture of pure oxygen and water vapor. By Dalton's Law of Partial Pressure, the pressure of pure oxygen is




The absolute temperature of oxygen gas is



The universal gas law constant for gmole, K, and mm Hg (torr) is .

By Ideal Gas Law, we can calculate the number of moles of oxygen gas as follows


 

From the decomposition of KClO3 by heating, 
 

Therefore, the amount of KClO3 is
 
 

Wednesday, April 29, 2015

Ideal Gas Law Problems

Category: Chemical Engineering Math

"Published in Newark, California, USA"

 What is the volume of 18.0 grams of pure water at 4°C and 1 atm?

Solution:

From the given word problem, it is about Ideal Gas Law because the weight, temperature, and pressure of pure water are given and we need to solve for the volume. 

The Ideal Gas Law is given by the equation


where:  

P = pressure of a gas or vapor
V =  volume of a gas or vapor
n = moles of a gas or vapor
T = absolute temperature of a gas or vapor
n = universal gas law constant

The number of moles of pure water is
 
 

The absolute temperature of pure water is 
 
 

The universal gas law constant for gmole, K, and atmosphere is .

Therefore, the volume of pure water is
 
 
 

Tuesday, April 28, 2015

Separation of Variables - Arbitrary Constant, 14

Category: Differential Equations

"Published in Newark, California, USA"

Find the particular solution for


when x = x0; v = v0.

Solution:

Consider the given equation above  



By separation of variables, transfer dx to the right side of the equation as follows 



Integrate on both sides of the equation, we have 





Substitute the values of v and x in order to solve for C as follows 




Therefore, the particular solution is 





Monday, April 27, 2015

Separation of Variables - Arbitrary Constant, 13

Category: Differential Equations

"Published in Newark, California, USA"

Find the particular solution for


when θ = 0, r = a.

Solution:

Consider the given equation above  


By separation of variables, transfer r³ to the left side of the equation as follows  



Integrate on both sides of the equation, we have  









Substitute the values of r and θ in order to solve for C as follows




 

Therefore, the particular solution is  





Take the inverse natural logarithm on both sides of the equation, we have