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Friday, May 31, 2013

Derivative - Hyperbolic Functions

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

Find the derivative for


Solution:

Consider the given equation above


Take the derivative of the above equation with respect to x, we have






We can accept the above equation as a final answer but if you wish to substitute the value of hyperbolic cosine, you can also do that one. We know that 




If 







then



becomes





The other way of getting the derivative of the given equation is to eliminate the hyperbolic functions by substituting their equivalent value or identity. We know that 



If



then substitute the value of hyperbolic sine of the above equation as follows









Take the derivative of the above equation with respect to x, we have









Thursday, May 30, 2013

Triple Integration

Category: Integral Calculus, Trigonometry

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Integrate first the given function with respect to dz, as follows





Integrate the above equation with respect to dr, as follows





Integrate the above equation with respect to dθ, as follows




Substitute the limits and the final answer is 





  





Wednesday, May 29, 2013

Double Integration

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate 

Solution:

Consider the given equation above


Integrate first the given function with respect to dy, as follows


If u = y, then du = dy. The above equation can be integrated into inverse trigonometric function





Integrate the above equation with respect to dx, as follows


Substitute the limits and the final answer is