Category: Algebra
"Published in Newark, California, USA"
Solve the following systems by substitution:
Solution:
Consider the given equations above
The first equation can be factored by the difference of the two cubes as follows
But
Hence, the above equation becomes
The second equation can be written as
Substitute the value of y to the above equation, we have
If you equate each factor to zero, then the values of x are -2 and 5.
If x = -2, then the value of y is
If x = 5, then the value of y is
Therefore, the solutions of the two equations are:
This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Showing posts with label Algebra. Show all posts
Showing posts with label Algebra. Show all posts
Sunday, November 16, 2014
Saturday, November 15, 2014
Solving Cubic Equations of Two Unknowns, 2
Category: Algebra
"Published in Newark, California, USA"
Solve the following systems by substitution:
Solution:
Consider the given equations above
The first equation can be factored by the difference of the two cubes as follows
But
Hence, the above equation becomes
The second equation can be written as
Substitute the value of y to the above equation, we have
If you equate each factor to zero, then the values of x are 3 and -2.
If x = 3, then the value of y is
If x = -2, then the value of y is
Therefore, the solutions of the two equations are:
"Published in Newark, California, USA"
Solve the following systems by substitution:
Solution:
Consider the given equations above
The first equation can be factored by the difference of the two cubes as follows
But
Hence, the above equation becomes
The second equation can be written as
Substitute the value of y to the above equation, we have
If you equate each factor to zero, then the values of x are 3 and -2.
If x = 3, then the value of y is
If x = -2, then the value of y is
Therefore, the solutions of the two equations are:
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