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Saturday, June 1, 2013

Indeterminate Form - Zero Over Zero, 3

Category: Differential Calculus, Algebra

"Published in Suisun City, California, USA"

Evaluate


Solution:

Consider the given equation above



Substitute the value of x which is 0 to the above equation, we have



Since the answer is 0/0, then it is considered as Indeterminate Form which is not accepted as a final answer in Mathematics. Remember this, any number, except zero divided by zero is always equal to infinity. If the Indeterminate form is either 0/0 or /, then we can use the L'Hopital's Rule in order to solve for these type of Indeterminate Forms. In this case, we can apply the L'Hopital's Rule for the above equation as follows



 

Substitute the value of x which is 0 to the above equation, we have


Since the answer is again 0/0, then we have to apply again the L'Hopital's Rule, as follows






Substitute the value of x which is 0 to the above equation, we have


Since the answer is again 0/0, then we have to apply again the L'Hopital's Rule, as follows




Substitute the value of x which is 0 to the above equation, we have


Therefore,

Friday, May 31, 2013

Derivative - Hyperbolic Functions

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

Find the derivative for


Solution:

Consider the given equation above


Take the derivative of the above equation with respect to x, we have






We can accept the above equation as a final answer but if you wish to substitute the value of hyperbolic cosine, you can also do that one. We know that 




If 







then



becomes





The other way of getting the derivative of the given equation is to eliminate the hyperbolic functions by substituting their equivalent value or identity. We know that 



If



then substitute the value of hyperbolic sine of the above equation as follows









Take the derivative of the above equation with respect to x, we have









Thursday, May 30, 2013

Triple Integration

Category: Integral Calculus, Trigonometry

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Integrate first the given function with respect to dz, as follows





Integrate the above equation with respect to dr, as follows





Integrate the above equation with respect to dθ, as follows




Substitute the limits and the final answer is