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Tuesday, June 4, 2013

Similar Triangles

Category: Plane Geometry

"Published in Newark, California, USA"

The points C and D in the figure lie on level ground in the same vertical plane with the tip B of the tower AB. If the tower AB is 300 ft. high and measurements give A1B1 = 5 ft., CA1 = 12 ft., A2B2 = 6 ft., and A2D = 8 ft., find the distance CD.

Photo by Math Principles in Everyday Life
















Solution:

The given problem above is asking for a distance of two points which is CD using similar triangles. The tower is located between CD and assuming that it is perpendicular to the ground. In this case, there are four right triangles in the figure. Label further the figure above, we have


Photo by Math Principles in Everyday Life

Consider ∆ABC:

Using similar triangles, we have









Consider ∆ABD:

Using similar triangles, we have







Therefore,








Monday, June 3, 2013

Variable Separation, 3

Category: Differential Equations, Integral Calculus, Algebra

"Published in Suisun City, California, USA"

Find the general solution for


Solution:

Consider the given equation above


The given equation above is a differential equation because it contains the differentials like dz and dt. We have to eliminate the differentials using the techniques of integration as follows







Using the separation of variables





Integrate on both sides of the equation






or



Multiply both sides of the equation by ez, we have







Sunday, June 2, 2013

More Integration Procedures, 9

Category: Integral Calculus, Trigonometry

"Published in Suisun City, California, USA"

Evaluate


Solution:

Consider the given equation above


There are two functions in the given equation which are x3 and sin x, respectively. If

 then

If
then

By applying the integration by parts, we have







Since the second term at the right side of the equation have two functions which are x2 and cos x, then we have to apply the integration by parts again. If

then

If
then

Again, by applying the integration by parts, we have







Therefore, the first integration by parts becomes







Since the second term at the right side of the equation have two functions which are x and sin x, then we have to apply the integration by parts again. If

then

If
then

Again, by applying the integration by parts, we have

 


 



Therefore, the final answer is