Algebraic Operations - Radicals, 12

Category: Algebra

"Published in Suisun City, California, USA"

Perform the indicated operations 

Solution:

Consider the given equation above

If you will multiply a radical with another radical with the same index, then the terms inside the radicals will be multiplied together. In this case, the given above equation can be written as follows

 

Apply the distributive property of multiplication over addition, as follows

Therefore, the final answer is

Algebraic Operations - Radicals, 11

Category: Algebra, Arithmetic

"Published in Suisun City, California, USA"

Perform the indicated operation

Solution:

Consider the given equation above

If you will cube a radical in which the index is 3 or that have a cube root sign, then the cube root sign in the equation will be cancelled.  

If you will multiply a radical with another radical with the same index, then the terms inside the radicals will be multiplied together. In this case, the given above equation can be written as follows

Although the above equation consists of numbers only, then we need to apply the principles of Binomial Theorem or cubing of a binomial because the radicals are treated as variables.

Therefore, the final answer is

Algebraic Operations - Radicals, 10

Category: Algebra, Arithmetic

"Published in Suisun City, California, USA"

Perform the indicated operations

Solution:

Consider the given equation above

If you will cube a radical in which the index is 2 or that have a square root sign, then the terms inside the square root sign will be raised to a third power.  

If you will multiply a radical with another radical with the same index, then the terms inside the radicals will be multiplied together. In this case, the given above equation can be written as follows 

Although the above equation consists of numbers only, then we need to apply the principles of Binomial Theorem or cubing of a binomial because the radicals are treated as variables.

At the first term, 3³ or 27 is not a perfect square. The factors of 27 are 9 and 3. 9 is a perfect square. 

At the second term, 3² or 9 is a perfect square. The square root of 9 is 3.  

Hence, the given equation above becomes

Therefore, the final answer is