Category: Differential Calculus, Algebra
"Published in Newark, California, USA"
Find the derivative for
Solution:
Consider the given equation above
The above equation is an exponential function but we cannot take the derivative by exponential function or even by power because the exponent of an algebraic function is also an algebraic function. In this type of exponential function, we need to take natural logarithm on both sides of an equation in order to eliminate the algebraic exponent of an algebraic function.
Take natural logarithm on both sides on an equation, we have
Take the derivative on both sides of the equation with respect to x
Multiply on both sides of the equation by y
but
Hence, the above equation becomes
Therefore, the final answer is

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Tuesday, July 16, 2013
Monday, July 15, 2013
Integration - Exponential Functions
Category: Integral Calculus, Algebra
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
Since 3 and e have the same exponent which is x, then we can rewrite the above equation as follows
If
then
Apply the Integration of Exponential Functions to the above equation, we have
Apply the Laws of Logarithm for the product of coefficients at the denominator
Therefore, the final answer is
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
Since 3 and e have the same exponent which is x, then we can rewrite the above equation as follows
If
then
Apply the Integration of Exponential Functions to the above equation, we have
Apply the Laws of Logarithm for the product of coefficients at the denominator
Therefore, the final answer is
Sunday, July 14, 2013
Solving Trigonometric Equations, 6
Category: Trigonometry
"Published in Suisun City, California, USA"
Solve for the value of x for
Solution:
Consider the given equation above
Rewrite secant, tangent, and cotangent into its equivalent function as follows
Divide both sides of the equation by sin x, we have
but
and the above equation becomes
Take the 4th root at both sides of the equation
Consider the positive value
Take the inverse tangent at both sides of the equation
Consider the negative value
Take the inverse tangent at both sides of the equation
Therefore, the final answers are
where n is the number of revolutions.
"Published in Suisun City, California, USA"
Solve for the value of x for
Solution:
Consider the given equation above
Rewrite secant, tangent, and cotangent into its equivalent function as follows
Divide both sides of the equation by sin x, we have
but
and the above equation becomes
Take the 4th root at both sides of the equation
Consider the positive value
Take the inverse tangent at both sides of the equation
Consider the negative value
Take the inverse tangent at both sides of the equation
Therefore, the final answers are
where n is the number of revolutions.
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