Category: Algebra, Arithmetic
"Published in Suisun City, California, USA"
Given the following matrices:
Carry out each indicated operations, or explain why it cannot be performed.
(a) A + B
(b) C - D
(c) C + A
(d) 5A
Solution:
(a) If you add the two matrices with the same dimensions, then each term or entry in a row or column will be added together. Therefore,
(b) If you subtract
the two matrices with the same dimensions, then each term or entry in a
row or column will be subtracted together. Therefore,
(c) C + A is undefined because we can't add matrices of different dimensions.
(d) If you multiply a matrix with any coefficient, variable, or any single term, then each term or entry will be multiplied by any coefficient, variable, or any single term as follows

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Friday, August 30, 2013
Thursday, August 29, 2013
Stoichiometry Problem - Material Balance
Category: Chemical Engineering Math, Algebra
"Published in Suisun City, California, USA"
The waste acid from a nitrating process containing 20% HNO3, 55% H2SO4, and 25% H20 by weight is to be concentrated by addition of concentrated sulfuric acid containing 95% H2SO4 and concentrated nitric acid containing 90% HNO3 to get desired mixed acid containing 26% HNO3 and 60% H2SO4. Calculate the quantities of waste and concentrated acids required for 1000 kg of desired mixed acid.
Solution:
The given word problem is about the mixing of different acids which involves the principles of Stoichiometry. The total amount of a substance in the reactants or incoming ingredients must be equal to the total amount of a substance in the final products. In short, the Law of Conservation of Mass must be followed all the time. Since all incoming substances are acids, then there's no chemical reactions involved in the mixture. To illustrate the given problem, it is better to draw the flow diagram as follows
Basis: 1000 kg of Desired Mixed Acid
Let x = be the amount of waste acid
y = be the amount of concentrated sulfuric acid
z = be the amount of concentrated nitric acid
Overall Material Balance around the Mixer:
Material Balance of Sulfuric Acid:
Material Balance for Nitric Acid:
Substitute the value of y and z to the first equation, we have
Substitute the value of x to the second equation, we have
Substitute the value of x to the third equation, we have
Therefore,
Amount of Waste Acid = 401.6 kg
Amount of Concentrated Sulfuric Acid = 398.65 kg
Amount of Concentrated Nitric Acid = 199.75 kg
"Published in Suisun City, California, USA"
The waste acid from a nitrating process containing 20% HNO3, 55% H2SO4, and 25% H20 by weight is to be concentrated by addition of concentrated sulfuric acid containing 95% H2SO4 and concentrated nitric acid containing 90% HNO3 to get desired mixed acid containing 26% HNO3 and 60% H2SO4. Calculate the quantities of waste and concentrated acids required for 1000 kg of desired mixed acid.
Solution:
The given word problem is about the mixing of different acids which involves the principles of Stoichiometry. The total amount of a substance in the reactants or incoming ingredients must be equal to the total amount of a substance in the final products. In short, the Law of Conservation of Mass must be followed all the time. Since all incoming substances are acids, then there's no chemical reactions involved in the mixture. To illustrate the given problem, it is better to draw the flow diagram as follows
![]() |
Photo by Math Principles in Everyday Life |
Basis: 1000 kg of Desired Mixed Acid
Let x = be the amount of waste acid
y = be the amount of concentrated sulfuric acid
z = be the amount of concentrated nitric acid
Overall Material Balance around the Mixer:
Material Balance of Sulfuric Acid:
Material Balance for Nitric Acid:
Substitute the value of y and z to the first equation, we have
Substitute the value of x to the second equation, we have
Substitute the value of x to the third equation, we have
Therefore,
Amount of Waste Acid = 401.6 kg
Amount of Concentrated Sulfuric Acid = 398.65 kg
Amount of Concentrated Nitric Acid = 199.75 kg
Wednesday, August 28, 2013
Rate, Distance, Time - Problem, 5
Category: Algebra
"Published in Newark, California, USA"
From Manila to a certain town in Batangas is some 224 miles. How long does it ordinarily take to reach the town, if by traveling 8 miles per hour faster, the trip is reduced by half an hour?
Solution:
The given word problem above is about rate, distance, and time problem with some conditions. Lets analyze the given word problem as follows:
Let x = be the rate in miles per hour
y = be the travel time in hour
We know that
The first working equation will be
If the statement says, "...if by traveling 8 miles per hour faster, the trip is reduced by half an hour?", then the second working equation will be
To eliminate y, substitute the value of y from the first working equation to the second equation, we have
Solve the quadratic equation by completing the square
Take the square root on both sides of the equation
In solving for the rate and time, we have to choose the positive value at the right side of the equation. Hence, the rate is
Therefore, the usual travel time is
"Published in Newark, California, USA"
From Manila to a certain town in Batangas is some 224 miles. How long does it ordinarily take to reach the town, if by traveling 8 miles per hour faster, the trip is reduced by half an hour?
Solution:
The given word problem above is about rate, distance, and time problem with some conditions. Lets analyze the given word problem as follows:
Let x = be the rate in miles per hour
y = be the travel time in hour
We know that
The first working equation will be
If the statement says, "...if by traveling 8 miles per hour faster, the trip is reduced by half an hour?", then the second working equation will be
To eliminate y, substitute the value of y from the first working equation to the second equation, we have
Solve the quadratic equation by completing the square
Take the square root on both sides of the equation
In solving for the rate and time, we have to choose the positive value at the right side of the equation. Hence, the rate is
Therefore, the usual travel time is
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