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Tuesday, September 17, 2013

Stoichiometry Problem - Material Balance, 8

Category: Chemical Engineering Math, Algebra

"Published in Newark, California, USA"

It is desired to have a mixed acid containing 10% HNO3, 43% H2SO4, and 17% H2O by weight. Sulfuric acid of 98% by weight is readily available. Calculate

(a) the strength of nitric acid, and
(b) the weight ratio of sulfuric acid to nitric acid.

Solution:

The given word problem is about the mixing of nitric acid and sulfuric acid which involves the principles of Stoichiometry. The strength or concentration of nitric acid is unknown and we need to solve it as well as the weight ratio of nitric acid and sulfuric acid. The total amount of a substance in the reactants or incoming ingredients must be equal to the total amount of a substance in the final products. In short, the Law of Conservation of Mass must be followed all the time. Since all incoming substances are acids, then there's no chemical reactions involved in the mixture. To illustrate the given problem, it is better to draw the flow diagram as follows 

Photo by Math Principles in Everyday Life

Since the weight of concentrated sulfuric acid, concentrated nitric acid, and mixed acid are not given in the problem, let's assign a basis of 100 kg of mixed acid in the problem.

Basis: 100 kg of Mixed Acid

Let x = be the amount of concentrated sulfuric acid
      y = be the amount of concentrated nitric acid

Overall Material Balance of Mixer:



Material Balance of H2SO4:





Substitute the value of x to the first equation, we have




The value of y which is the amount of the concentrated nitric acid is not a pure nitric acid. We need first to get the amount of pure nitric acid in order to get the strength or concentration of concentrated nitric acid.

Material Balance of HNO3:



Therefore, the strength or concentration of concentrated nitric acid is
 




The weight ratio of conc. H2SO4 to conc. HNO3 is




Monday, September 16, 2013

Stoichiometry Problem - Material Balance, 7

Category: Chemical Engineering Math, Algebra

"Published in Newark, California, USA"

The waste acid from a nitrating process contains 30% H2SO4, 35% HNO3, and 35% H2O by weight. The acid is to be concentrated to contain 39% H2SO4 and 42% HNO3 by addition of 10% oleum and concentrated nitric acid containing 72% HNO3 by weight. Calculate the amount of waste acid, oleum, and concentrated nitric acid to be mixed to get 1000 kg of desired mixed acid.

Solution:

The given word problem is about the mixing of acids and oleum which involves the principles of Stoichiometry. The total amount of a substance in the reactants or incoming ingredients must be equal to the total amount of a substance in the final products. In short, the Law of Conservation of Mass must be followed all the time. Since all incoming substances are acids, then there's no chemical reactions involved in the mixture. To illustrate the given problem, it is better to draw the flow diagram as follows

Photo by Math Principles in Everyday Life

Basis: 1000 kg of Desired Mixed Acid

Let x = be the amount of Waste Acid
      y = be the amount of Concentrated Nitric Acid
      z = be the amount of Oleum

Overall Material Balance of Mixer:


Material Balance of HNO3:





Oleum is a chemical substance which consist of the mixture of sulfuric acid and sulfur trioxide. If you have 100 kg of 10% oleum, then you have 10 kg of SO3 and 90 kg of H2SO4

We can express SO3 in terms of H2SO4 by gravimetric analysis as follows


From the chemical equation above, if 1 kmol SO3 = 1 kmol H2SO4, then it follows that their molecular weight will be equal to 80 kg SO3 = 98 kg H2SO4.

The weight of H2SO4 in SO3 can be calculated as follows



The total weight of H2SO4 in oleum is



Hence, the % of H2SO4 in solution is



Oleum is a highly concentrated H2SO4 than the regular concentrated H2SO4 because the % H2SO4 is more than 100%.

 Material Balance of H2SO4:





Substitute the values of y and z to the first equation, we have






Substitute the value of x to the second equation, we have





Substitute the value of x to the third equation, we have





Therefore,

Amount of Waste Acid = 159.93 kg
Amount of Concentrated HNO3 = 505.57 kg
Amount of 10% Oleum = 334.50 kg

Sunday, September 15, 2013

Stoichiometry Problem - Material Balance, 6

Category: Chemical Engineering Math, Algebra

"Published in Newark, California, USA"

A sample of coal is found to contain 63% carbon and 24% ash on weight basis. The analysis of refuse after combustion shows 7% carbon and the rest ash. Calculate the percentage of the original carbon unburnt in the refuse. 

Solution:

The given word problem is about the combustion of a coal in a furnace which involves the principles of Stoichiometry. When you add the percent compositions of a coal, it will not be equal to 100%. The rest of the composition of a coal is either water or other substances that are mostly combustible. During the combustion of a coal, the components like carbon, water, ash, and other substances are converting into flue gas and refuse. The flue gas is a mixture of carbon dioxide, carbon monoxide, water vapor, oxygen, nitrogen, and other oxide gases. The refuse is mostly ash but sometimes there are unburnt carbon or coal in the refuse. The total amount of a substance in the reactants or incoming ingredients must be equal to the total amount of a substance in the final products. In short, the Law of Conservation of Mass must be followed all the time. To illustrate the problem, it is better to draw the flow diagram as follows

Photo by Math Principles in Everyday Life

Since the amount of coal, flue gas, and refuse are not given in the problem, let's assign a basis of 100 kg of coal in the problem.

Basis: 100 kg of coal

Let x = be the amount of refuse
      y = be the amount of flue gas

Material Balance of Ash:







Therefore,