Category: Algebra
"Published in Newark, California, USA"
Subtract the sum of the first two expressions from the sum of the remaining expressions:
Solution:
The first that we have to do is to group the subtrahend and minuend. The subtrahend is the sum of the first two polynomials while the minuend is the sum of the rest of the polynomials. Hence,
Change the sign of the subtrahend and perform the addition, we have
Therefore, the final answer is

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Thursday, October 10, 2013
Wednesday, October 9, 2013
Adding - Subtracting Polynomials, 2
Category: Algebra
"Published in Newark, California, USA"
Add the following polynomials:
Solution:
The first thing that we have to do is to group each term according to their variables. Like combines like. When you combine similar or like terms, please be very careful especially with the signs. Consider the given equation above
Since we will add all the given polynomials above, then we don't have to change the sign of each terms. Group the given polynomials according to their variables, we have
Therefore, the final answer is
"Published in Newark, California, USA"
Add the following polynomials:
Solution:
The first thing that we have to do is to group each term according to their variables. Like combines like. When you combine similar or like terms, please be very careful especially with the signs. Consider the given equation above
Since we will add all the given polynomials above, then we don't have to change the sign of each terms. Group the given polynomials according to their variables, we have
Therefore, the final answer is
Tuesday, October 8, 2013
Integration - Miscellaneous Substitution, 2
Category: Integral Calculus, Trigonometry
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
You notice that the denominator contains trigonometric functions and we cannot integrate it by simple integration. This is a difficult one because the numerator has no trigonometric functions. If you will use the integration by parts, then the above equation will be more complicated and there will be an endless repetition of the procedure.
For this type of a function, like the given equation above, we can integrate it by Miscellaneous Substitution. Let's proceed with the integration technique as follows
Let
From double angle formula,
Since the given problem has Cosine function, then we can get the values of Sine and Cosine functions from Tangent function as follows
Using the figure above that
From the given problem
Substitute the values of dx, Sin x, and Cos x to the above equation, we have
The above equation can now be integrated by Inverse Trigonometric Function Formula as follows
but
Therefore,
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
You notice that the denominator contains trigonometric functions and we cannot integrate it by simple integration. This is a difficult one because the numerator has no trigonometric functions. If you will use the integration by parts, then the above equation will be more complicated and there will be an endless repetition of the procedure.
For this type of a function, like the given equation above, we can integrate it by Miscellaneous Substitution. Let's proceed with the integration technique as follows
Let
From double angle formula,
Since the given problem has Cosine function, then we can get the values of Sine and Cosine functions from Tangent function as follows
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Photo by Math Principles in Everyday Life |
Using the figure above that
From the given problem
Substitute the values of dx, Sin x, and Cos x to the above equation, we have
The above equation can now be integrated by Inverse Trigonometric Function Formula as follows
but
Therefore,
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