Free counters!

Tuesday, October 29, 2013

Special Products - Factoring, 18

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


The two terms are both perfect square but we cannot factor the given equation by the difference of two squares because both terms are positive and the other one must be negative in order to factor the given equation. Let's rewrite the given equation in terms of power as follows





The two terms are now expressed in terms of power or exponent. Since their exponents are multiples of three, then we can factor the given equation by the sum and difference of two cubes. Therefore, the factors are






 

Monday, October 28, 2013

Special Products - Factoring, 17

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


Since the two terms have both odd exponents which is 7, then we can factor the given equation by the sum and difference of two like odd powers. Therefore, the factors are



Sunday, October 27, 2013

Special Products - Factoring, 16

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


Since the two terms have both even exponents, then we can factor the given equation by the sum and difference of two squares as follows



Factor each group by the sum and difference of two cubes as follows



Therefore, the factors are