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Friday, November 8, 2013

Special Products - Factoring, 28

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


If you think that you cannot factor the given equation, then you're right because there's no common factor at each terms. How about if you will expand the given equation and combine similar terms, then we can factor the resulting equation if possible? Let's expand the given equation, we have



Arrange the above equation according to their variables,



The last term, which is 3xyz can be written into three xyz's as follows



Group the above equation according to their variables, we have



Insert xyz at each group,



Remove their common factor at each group,




Since their common factor is (x - y + z), therefore, the factors of the given equation are




Thursday, November 7, 2013

Special Products - Factoring, 27

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


Did you notice that the given equation is a quadratic equation of variables (x - 9b) and y? (x - 9b) is considered as a single variable.  We have to do the trial and error method in getting the factors of (x - 9b)² and -2y² so that the middle term must be -(x - 9b)y. Let's start the factoring of the given equation as follows



The middle term is



Since the value of the above calculation is the same as the middle term of the given equation which is -y(x - 9b), then the factors of the given equation are 

 

Wednesday, November 6, 2013

Special Products - Factoring, 26

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


Did you notice that the given equation is a quadratic equation of variable y? The coefficient of three terms are also variables. In this type of quadratic equation, we have to do the trial and error method in factoring until we get the desired middle term. The coefficient of y² can be factored into (x + 1)(x - 1) while x² into x•x. Let's start the factoring of the given equation as follows



The middle term is




Since the value of the above calculation is the same as the middle term of the given equation which is -2xy, then the factors of the given equation are