Category: Algebra
"Published in Newark, California, USA"
Simplify
Solution:
Consider the given equation above
The first thing that we have to do is to see if the quadratic equations at the numerator and denominator can be factored or not. Since x² has coefficient on both numerator and denominator, then we have to do factoring by trial and error until we get the middle term. Let's factor the numerator and denominator as follows
The
greatest common factor (GCF) of the numerator and denominator is (2x + 3y). Cross out their GCF and simplify into lowest term. Therefore, the
final answer is
Category: Algebra
"Published in Newark, California, USA"
Simplify
Solution:
Consider the given equation above
The numerator has similar variables and the denominator is a quadratic equation of the difference of two squares. Let's group the numerator with similar variables as follows
Take out their common factor at each group, we have
Factor the denominator as the difference of two squares
The
greatest common factor (GCF) of the numerator and denominator is (a + 2). Cross out their GCF and simplify into lowest term. Therefore, the
final answer is
Category: Algebra
"Published in Newark, California, USA"
Simplify
Solution:
Consider the given equation above
The numerator is a quadratic equation in terms of y and mx while the denominator has a common factor which is x. Let's factor the given equation, we have
The greatest common factor (GCF) of the numerator and denominator is (y + 2mx). Cross out their GCF and simplify into lowest term. Therefore, the final answer is
