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Wednesday, December 11, 2013

Integration - Algebraic Functions, Powers

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The given equation can also be written as



Applying the integration by power formula, we have




Therefore,


where C is the constant of integration.

 

Tuesday, December 10, 2013

Derivative - Algebraic Functions, Powers, 10

Category: Differential Calculus

"Published in Newark, California, USA"

Find y' for


Solution:

Consider the given equation above


Did you notice that the numerator is a product of two binomials? Let's get the product of two binomials at the numerator as follows




Since the denominator consists of only one term, then we can rewrite the given equation as follows




Take the derivative with respect to x as follows






Therefore, the answer is

  

Monday, December 9, 2013

Derivative - Algebraic Functions, Powers, 9

Category: Differential Calculus

"Published in Newark, California, USA"

Find y' for


Solution:

Consider the given equation above


Since the denominator consists of only one term, then we can rewrite the given equation as follows




Take the derivative with respect to x as follows







Therefore, the answer is