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Friday, December 20, 2013

Integration - Algebraic Functions, Powers, 10

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The first thing that we have to do is to square the given equation as follows





Apply the integration by power formula, we have








Therefore, the answer is


where C is the constant of integration.
 

Thursday, December 19, 2013

Integration - Algebraic Functions, Powers, 9

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Since the denominator consists of only one term, then we can rewrite the given equation as follows






Apply the integration by power formula, we have






Therefore, the answer is


where C is the constant of integration.
 

Wednesday, December 18, 2013

Integration - Algebraic Functions, Powers, 8

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Although the exponent of x is a fraction, then we can also apply the integration by power formula as follows






Therefore, the answer is


where C is the constant of integration.