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Friday, January 24, 2014

Finding Equation - Circle, 3

Category: Analytic Geometry, Plane Geometry

"Published in Newark, California, USA"

Find the equation of a circle having as diameter the line segment from (-1, 1) to (3, 4).

Solution

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

The first thing that we need to do is to get the center of a circle by using the midpoint formula of the two points as follows









Hence, the center of a circle is C (1, 5/2).

Next, get the radius of a circle by using the distance formula of two points as follows 









Therefore, the equation of a circle is




 

Thursday, January 23, 2014

Finding Equation - Circle, 2

Category: Analytic Geometry, Plane Geometry

"Published in Vacaville, California, USA"

Find the equation of a circle if the endpoints of a diameter are A (-1, 3) and B (7, -5).

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

The first thing that we need to do is to get the center of a circle by using the midpoint formula of the two points as follows


 
 
 
 
 
 

Hence, the center of a circle is C (3, -1).

Next, get the radius of a circle by using the distance formula of two points as follows
 
 
 
 
 
   
Therefore, the equation of a circle is
 
 
 
 

Wednesday, January 22, 2014

Finding Equation - Circle

Category: Analytic Geometry, Plane Geometry, Algebra

"Published in Newark, California, USA"

Find the equation of a circle that is tangent to both axes, center in second quadrant and radius is 2.

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

When you say tangent, it is perpendicular. In this case the radius of a circle is perpendicular to x-axis and y-axis. If a circle is located at the second quadrant, the center is C (-2, 2). Therefore, the equation of a circle is