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Sunday, March 23, 2014

Solving 3rd Order Differential Equations, 2

Category: Differential Equations, Integral Calculus

"Published in Newark, California, USA"

Find the general solution for


Solution:

Consider the given equation above


The given equation is a 3rd Order Differential Equation because the third derivative of y with respect to x is involved. We can rewrite given equation as follows



Multiply both sides of the equation by dx, we have




Integrate on both sides of the equation, we have 




Rewrite the above equation as follows 



Multiply both sides of the equation by dx, we have 




Integrate on both sides of the equation, we have 






Multiply both sides of the equation by dx, we have 




Integrate on both sides of the equation, we have 







where

 

Saturday, March 22, 2014

Solving 2nd Order Differential Equations, 2

Category: Differential Equations, Integral Calculus

"Published in Newark, California, USA"

Find the general solution for


Solution:

Consider the given equation above


The given equation is a 2nd Order Differential Equation because the second derivative of y with respect to x is involved. We can rewrite given equation as follows



Multiply both sides of the equation by dx, we have 




Integrate on both sides of the equation, we have 




Multiply both sides of the equation by dx, we have 


Multiply both sides of the equation by dx, we have 




Integrate on both sides of the equation, we have 



Consider


If 


then


If 


then


Hence, by integration by parts




Substitute the above equation to the original equation, we have






where

 

Friday, March 21, 2014

Definite Integral - Algebraic Functions, Powers, 10

Category: Integral Calculus, Algebra

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The first thing that we have to do is to integrate the given equation above, we have








The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have










Therefore,