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Wednesday, February 11, 2015

Right Circular Cylinder Problems, 19

Category: Solid Geometry

"Published in Newark, California, USA"

How long a wire 0.1 in. in diameter can be drawn from a block of copper 2 in. by 4 in. by 6 in.?

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

The volume of a block of copper is


   

Therefore, the length of a wire that can be drawn from a block of copper assuming that a wire is a right circular cylinder is equal to




                       or
 

Tuesday, February 10, 2015

Right Circular Cylinder Problems, 18

Category: Solid Geometry

"Published in Newark, California, USA"

How much wood is wasted in turning out the largest possible cylindrical rod from a stick whose uniform square cross-sectional area is 10 sq. in. and whose length is 5 ft.?

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

In this problem, the diameter of a circle is not given. Since the area of a cross-section of a stick is given which is a square, then we can solve for the sides of a square which is also a diameter of a circle as follows




Therefore, the amount of wood wasted in turning out the largest possible cylindrical rod from a stick is








Monday, February 9, 2015

Right Circular Cylinder Problems, 17

Category: Solid Geometry

"Published in Newark, California, USA"

A cylindrical tin can holding 2 gal. has its height equal to the diameter of its base. Another cylindrical tin can with the same capacity has its height equal to twice the diameter of its base. Find the ratio of the amount of tin required for making the two cans with covers.

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

The volume of a tin can in cubic inches is



If the height of a tin can equals its diameter, then the diameter is







Hence, the total area of a tin can is








If the height of a tin can is twice its diameter, then the diameter is 







Hence, the total area of a tin can is 











Therefore, the ratio of the amount of tin required for making the two cans with covers is