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Sunday, October 28, 2012

Temperature Conversion Equation

Category: Algebra, Chemical Engineering Math

"Published in Newark, California, USA"

The students are performing their experiment in Physics Lab to observe and record the temperature of freezing water and boiling water with the use of ºC thermometer and ºF thermometer.  At their first experiment, the two thermometers are dipped together in a beaker filled with water. If a beaker is placed inside the freezer, the water is starting to freeze at 0 ºC and 32 ºF. At their second experiment, the two thermometers are dipped together in another beaker filled with water. If a beaker is placed at the top of the heating plate, the water is starting to boil at 100 ºC and 212 ºF. From the temperature readings of two thermometers, how do you convert the temperature reading from ºC to ºF and vice versa? At what temperature is the ºC and ºF readings will be equal?

Solution:

The first thing that you have to do is to draw the two thermometers with the observed temperature readings for the freezing point and boiling point of water.

Photo by Math Principles in Everyday Life

Next, we have to assign the unknown readings at the middle of the two thermometers. From the given figure, the problem type is likely the ratio and proportion. Further label the figure, we have,


Photo by Math Principles in Everyday Life

Using the ratio and proportion,






or we can rewrite the above equation as




If oF = oC,



                                        oF = - 40


Saturday, October 27, 2012

Variable Separation

Category: Differential Equations, Integral Calculus

"Published in Newark, California, USA"

Find the general solution for the equation:


Solution:

If you examine the above equation, it is a differential equation because it contains the differentials like dx and dy. Our goal is to eliminate the differentials by integration but before that, let's examine the above equation. We have to do first the grouping at the right side of the equation and then factor all the terms if there are any common factors. The above equation can be written as




You noticed that we are applying the principles of factoring for the above equation. You must know the principles of Algebra, Trigonometry, and Calculus very well in solving Differential Equations. Next, we want to eliminate y at the left side of the equation and also we want to eliminate x at the right side of the equation. If you will divide both sides of the equation by (y + 1)(x2 +1), then the above equation becomes


Now, looking at the right side of the equation, the exponential degree at the numerator is greater than at the denominator. We have to do the division first as follows
                                         

The above equation can be written as



Next, integrate on both sides of the equation




Multiply both sides by 2 to eliminate the fraction, we have


A constant (C) multiply by any number is still a constant.

Note: In some cases, C can be written as ln C after the integration. It's up to you. The natural logarithm of any constant is still a constant. 

Friday, October 26, 2012

Deriving Half Angle Formula

Category: Trigonometry

"Published in Newark, California, USA"

Last October 24, 2012, we did the derivation of Double Angle Formula. Right now, we will derive the formulas for Half Angle Formula from the formulas of Double Angle Formula. 

Let's consider this one,


but 
 
 
 
then the above equation becomes
 
 
 

If A = 2θ, then θ = ½ A




Take the square root on both sides of the equation,


Again, let's consider this one,


but



then the above equation becomes
 
 
 
 

If A = 2θ, then θ = ½ A




Take the square root on both sides of the equation,


How about for Tangent function? Well, let's derive for Tangent function. We know that




You can consider the above formula for Tangent function but there's a rule in Mathematics that the denominator must be free from radicals. Let's rationalize the denominator as follows: