Category: Trigonometry
"Published in Newark, California, USA"
Solve for the unknown angle for
Solution:
The first that we have to do is to reduce the higher angles in order to simplify the given equation. Consider the given equation above
Apply the Sum and Product of Two Angles Formula in order to reduce the higher angles as follows
Equate each factor to zero, we have
for
and
where n = number of revolutions.
for
and
and
where n = number of revolutions.
This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Monday, January 28, 2013
Sunday, January 27, 2013
Word Problem - Average Problem
Category: Algebra
"Published in Newark, California, USA"
Lilian's average in 3 quizzes is 80%. If she made 5% more in the first than in the second and 8% less in the third, what grades did she get in the three quizzes?
Solution:
The given item in a word problem is the average of the three quizzes of Lilian with conditions of her quizzes and we have to find the grades of her quizzes as follows
Let x = the score of her 2nd quiz
x + 5% = the score of her 1st quiz
x - 8% = the score of her 3rd quiz
Average of three quizzes = ⅓(1st Quiz + 2nd Quiz + 3rd Quiz)
80% = ⅓ (x + 5% + x + x - 8%)
3x - 3% = 240%
3x = 240% + 3%
3x = 243%
x = 81%
Therefore
Lilian's grade in 1st Quiz = x + 5% = 81% + 5% = 86%
Lilian's grade in 2nd Quiz = x = 81%
Lilian's grade in 3rd Quiz = x - 8% = 81% - 8% = 73%
"Published in Newark, California, USA"
Lilian's average in 3 quizzes is 80%. If she made 5% more in the first than in the second and 8% less in the third, what grades did she get in the three quizzes?
Solution:
The given item in a word problem is the average of the three quizzes of Lilian with conditions of her quizzes and we have to find the grades of her quizzes as follows
Let x = the score of her 2nd quiz
x + 5% = the score of her 1st quiz
x - 8% = the score of her 3rd quiz
Average of three quizzes = ⅓(1st Quiz + 2nd Quiz + 3rd Quiz)
80% = ⅓ (x + 5% + x + x - 8%)
3x - 3% = 240%
3x = 240% + 3%
3x = 243%
x = 81%
Therefore
Lilian's grade in 1st Quiz = x + 5% = 81% + 5% = 86%
Lilian's grade in 2nd Quiz = x = 81%
Lilian's grade in 3rd Quiz = x - 8% = 81% - 8% = 73%
Saturday, January 26, 2013
First Order Linear Equation, 2
Category: Differential Equations, Trigonometry, Integral Calculus
"Published in Newark, California, USA"
Find the particular solution for
when
Solution:
Consider the given equation
If
then
If
then
Since
then the given equation is not an Exact Equation. We need to find the integrating factor first and then multiply it on both sides of an equation so that the given equation becomes an Exact Equation.
Consider again the given equation
Arrange the above equation into its standard form as follows
where
and
The integrating factor is
The general solution for the above equation is
If
then
Therefore, the particular solution for the above equation is
We can consider the above equation as a final answer but if you want to further simplify the above equation, consider the Half Angle Formula as follows
Hence, the above equation becomes
"Published in Newark, California, USA"
Find the particular solution for
when
Solution:
Consider the given equation
If
then
If
then
Since
then the given equation is not an Exact Equation. We need to find the integrating factor first and then multiply it on both sides of an equation so that the given equation becomes an Exact Equation.
Consider again the given equation
Arrange the above equation into its standard form as follows
where
and
The integrating factor is
The general solution for the above equation is
If
then
Therefore, the particular solution for the above equation is
We can consider the above equation as a final answer but if you want to further simplify the above equation, consider the Half Angle Formula as follows
Hence, the above equation becomes
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