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Sunday, October 6, 2013

Integration - Trigonometric Functions, 9

Category: Integral Calculus, Trigonometry

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The given equation above has both trigonometric functions at the numerator and the denominator. The denominator contains logarithmic function of a trigonometric function. We need to assign u by considering the complicated part in the equation.

If 



then it follows that




 
Since the numerator has the same du, then the above equation can be integrated by simple integration as follows


Saturday, October 5, 2013

Integration - Exponential Functions, 2

Category: Integral Calculus, Algebra

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Since the numerator is greater than the denominator, then we have to do the division of polynomial as follows


The above equation becomes


If


then


Therefore,


 

Friday, October 4, 2013

Integration - Algebraic Substitution, 4

Category: Integral Calculus, Algebra

"Published in Newark, California, USA"

Evaluate:


Solution:

Consider the above equation


The above equation cannot be integrated by simple integration because one of the variables has a radical sign. We need to eliminate the radical sign by substituting with another variable as follows

Let




So that the above equation becomes







but 


Therefore,