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Tuesday, October 8, 2013

Integration - Miscellaneous Substitution, 2

Category: Integral Calculus, Trigonometry

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


You notice that the denominator contains trigonometric functions and we cannot integrate it by simple integration. This is a difficult one because the numerator has no trigonometric functions. If you will use the integration by parts, then the above equation will be more complicated and there will be an endless repetition of the procedure.  

For this type of a function, like the given equation above, we can integrate it by Miscellaneous Substitution. Let's proceed with the integration technique as follows 

Let





From double angle formula,



Since the given problem has Cosine function, then we can get the values of Sine and Cosine functions from Tangent function as follows 

Photo by Math Principles in Everyday Life

Using the figure above that



From the given problem


Substitute the values of dx, Sin x, and Cos x to the above equation, we have








The above equation can now be integrated by Inverse Trigonometric Function Formula as follows



but


Therefore,

  

Monday, October 7, 2013

Integration - Algebraic Substitution, 5

Category: Integral Calculus, Algebra

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


Since the denominator consists of a binomial and a radical equation, then we cannot integrate it by simple integration. We need to simplify first the given equation by eliminating the radical sign by algebraic substitution.

Let




then it follows that


Hence, the above equation becomes




The denominator at the right side of the equation can be factored as follows


Since the denominator is already factored, then we can rewrite the above equation into partial fractions as follows


Consider



Multiply both sides of the equation by their Least Common Denominator (LCD), we have


 
 

Equate u:


 

Equate u0:



but


The above equation becomes






Substitute the values of A and B to the original equation, we have


 
 
 
 

but



Therefore,