Free counters!

Sunday, November 3, 2013

Special Products - Factoring, 23

Category: Algebra

"Published in Suisun City, California, USA"

Find the factors for


Solution:

Consider the given equation above


Did you notice that the first four terms of the given equation is a perfect cube? Well, let's group the first four terms as follows



Next, rewrite the grouped terms in terms of exponential function as follows



Since 64 is a perfect cube, then we can factor the above equation by the difference of two cubes. Therefore, the factors of the given equation are









Saturday, November 2, 2013

Special Products - Factoring, 22

Category: Algebra

"Published in Suisun City, California, USA"

Find the factors for


Solution:

Consider the given equation above


In factoring of any polynomial, we have to do the trial and error aside from inspecting the terms of a given equation. Well, let's do the grouping of the equation into two terms as follows



Remove the common factor of each group, we have



Since the three groups have their common factor which is (x + 2b), therefore, the factors of the given equation are



Friday, November 1, 2013

Special Products - Factoring, 21

Category: Algebra

"Published in Newark, California, USA"

Find the factors for 


Solution:

Consider the given equation above


You notice that there are five terms at the given equation, which means that we have to group three terms and then another group for the rest of the terms. If you look at the given equation, the first two terms and the last term will be a perfect trinomial square if you group them. Let's arrange the given equation and group the terms as follows


 



Take out their common factor which is (m - 2n), and therefore, the factors of the given equation are