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Monday, December 2, 2013

Derivative - Algebraic Functions, Powers, 2

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

Find y' for


Solution:

Consider the given equation above


Since the given equation is a product of two binomials, then we have to get the derivative of the given equation using the derivative by product formula as follows






Therefore, the answer is

 

Sunday, December 1, 2013

Derivative - Algebraic Functions, Powers

Category: Differential Calculus, Algebra

"Published in Newark, California, USA"

Find y' for


Solution:

Consider the given equation above


There are two ways in getting the derivative of the given equation. First, you can get the product of two functions first by applying the distributive property of multiplication over addition and then apply the derivative by power formula. Let's get the derivative of the given equation as follows





You can also get the derivative of the given equation by product formula as follows







Note: The derivative of any constant is always equal to zero.
 

Saturday, November 30, 2013

Proving Trigonometric Identities, 19

Category: Trigonometry

"Published in Suisun City, California, USA"

Prove that


Solution:

Consider the given equation above


In proving the trigonometric identities, we have to choose the more complicated part which is the left side of the equation. We have to use the principles of simplifying trigonometric functions as much as we can until we get the same equation as the right side of the equation. Let's rewrite the rational and reciprocal functions into its equivalent function as follows






but



Hence, the above equation becomes



Therefore,