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Thursday, December 12, 2013

Integration - Algebraic Functions, Powers, 2

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


There are two ways in getting the integral of the given equation with respect to x. 

1st Method: We can do the integral of each term by power formula as follows






Therefore,


where C is the constant of integration.

2nd Method: We can do the integral of the whole function by power formula as follows


where u is a function of x and du is the differential of a function with respect to x. In this case, let's consider again the given equation


If u = (x - 7), then du = dx. Since, the power formula is applicable to the given equation, then we can integrate the given equation by power formula as follows




Therefore,


where C is the constant of integration.


Wednesday, December 11, 2013

Integration - Algebraic Functions, Powers

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The given equation can also be written as



Applying the integration by power formula, we have




Therefore,


where C is the constant of integration.

 

Tuesday, December 10, 2013

Derivative - Algebraic Functions, Powers, 10

Category: Differential Calculus

"Published in Newark, California, USA"

Find y' for


Solution:

Consider the given equation above


Did you notice that the numerator is a product of two binomials? Let's get the product of two binomials at the numerator as follows




Since the denominator consists of only one term, then we can rewrite the given equation as follows




Take the derivative with respect to x as follows






Therefore, the answer is