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Wednesday, December 25, 2013

Variable Separation, 5

Category: Differential Equations, Integral Calculus

"Published in Suisun City, California, USA"

Find the general solution for


Solution: 

Consider the given equation above


The given equation can be written as




Arrange the above equation by separation of variables, we have




Integrate on both sides of the equation, we have






Therefore, the general solution is


You can also eliminate their fraction by multiplying both sides of the equation by their Least Common Denominator (LCD) which is 4 as follows





Note: A constant multiply by another constant or coefficient is still a constant. 
 

Tuesday, December 24, 2013

Variable Separation, 4

Category: Differential Equations, Integral Calculus

"Published in Suisun City, California, USA"

Find an equation of a curve that passes thru the point (1, 1) and whose slope at (x, y) is y²/x³.

Solution:

The slope of a curve is a first derivative of the equation of a curve with respect to x. In this problem, the slope of a curve at (x, y) is written as



Arrange the above equation by separation of variables, we have







Integrate on both sides of the equation in order to get the equation of a curve as follows















To solve for the value of C, substitute the value of x and y which is the given point in the curve, as follows









Therefore, the equation of the curve is



Multiply both sides of the equation by their Least Common Denominator, which is 2x²y, we have













Therefore, the equation of a curve is


Monday, December 23, 2013

Integration - Algebraic Functions, Powers, 13

Category: Integral Calculus

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The first thing that we have to do is to take out the coefficient as follows





Apply the integration by power formula, we have









Therefore, the answer is


where C is the constant of integration.