Free counters!

Sunday, October 5, 2014

Word Problem - Number Problem, 4

Category: Algebra

"Published in Vacaville, California, USA"

The sum of two numbers is twice their difference. The larger number is 6 more than twice the smaller. Find the numbers.

Solution:

From the description of a given word problem, it is an application of linear equation with one variable.

Let x = be the value of a smaller number
      2x + 6 = be the value of a larger number

From the statement "The sum of two numbers is twice their difference.", then the working equation is

  
From the working equation, we can solve for the value of x which is the value of a smaller number as follows







The value of a larger number is




Therefore, the numbers are 6 and 18


Saturday, October 4, 2014

Word Problem - Mixture Problem

Category: Algebra

"Published in Vacaville, California, USA"

A customer in a coffee shop wishes to purchase a blend of two coffees: Kenyan, costing $ 3.50 a pound, and Sri Lankan, costing $ 5.60 a pound. He ends up buying 3 lbs of such as blend, which costs him $11.55. How many pounds of each kind went into the mixture?

Solution:

From the description of a given word problem, it is an application of linear equation with two equations, two unknowns.  

Let x be the number of pounds of Kenyan coffee
      y be the number of pounds of Sri Lankan coffee

From the statement "He ends up buying 3 lbs of such as blend,..", then the working equation is


From the statement "A customer in a coffee shop wishes to purchase a blend of two coffees: Kenyan, costing $ 3.50 a pound, and Sri Lankan, costing $ 5.60 a pound....which costs him $11.55.", then the working equation is
 

Hence, the working equations for the given problem are
 


From the first equation,
 
 

Substitute the value of x to the second equation, we have
 
 





Substitute the value of y to any of two equations, we have



 

Therefore, a customer needs to buy a mixture of 2.5 pounds of Kenyan coffee and 0.5 pounds of Sri Lankan coffee that cost $11.55.

  

Friday, October 3, 2014

Word Problem - Coin Problem

Category: Algebra

"Published in Vacaville, California, USA"

A man has 14 coins in his pocket, all of which are dimes and quarters. If the total value of his change is $ 2.75, how many dimes and how many quarters does he have?

Solution:

From the description of a given word problem, it is an application of linear equation with two equations, two unknowns.  

Let x = be the number of dimes or 10 cent coins
      y = be the number of quarters or 25 cent coins
 
From the statement "A man has 14 coins in his pocket, all of which are dimes and quarters.", then the working equation is


From the statement "If the total value of his change is $ 2.75,..", then the working equation is

  
Hence, the working equations for the given problem are



From the first equation,



Substitute the value of y to the second equation, we have







Substitute the value of x to any of two equations, we have





Therefore, there are 5 coins of dime and 9 coins of quarter in his pocket. 

Check: