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Tuesday, December 30, 2014

Right Triangle Problems

Category: Plane Geometry

"Published in Vacaville, California, USA"

A city lot has the shape of a right triangle whose hypotenuse is 7 ft longer than one of the other sides. The perimeter of the lot is 392 ft. How long is each of the three sides of the lot?

Solution:

To illustrate the problem, it is better to draw the figure as follows

Photo by Math Principles in Everyday Life

Since there are two unknown variables for a right triangle, then we need to have two working equations in order to solve for the values of two variables.

The first working equation that we will use is Pythagorean Theorem because the figure is a right triangle. The first working equation is





Next, we need a second working equation which is the perimeter of a right triangle because it is given in the problem. The second working equation is





Substitute the value of b to the first working equation, we have






Since -1554 is not divisible by 4, then we have to use quadratic formula as follows







If you will choose a positive sign, then the value of a is





Hence, the value of b is





Since the value of b is negative, then we cannot accept the values of a and b in the first condition.

If you will choose a negative sign, then the value of a is 





Hence, the value of b is

  



and the value of c is




Therefore, the dimensions of a city lot are 168 ft, 49 ft, and 175 ft

Monday, December 29, 2014

Circular Segment Problems, 2

Category: Plane Geometry

"Published in Newark, California, USA"

Find the area of the shaded region:

Photo by Math Principles in Everyday Life

Solution:

Consider the given figure above

Photo by Math Principles in Everyday Life

The first thing that we need to do is to label further the given figure so that we can solve for the area of circular segment which is the unshaded portion as follows

Photo by Math Principles in Everyday Life

The angle of an arc is equal to the angle of circular sector which is 120°. If you draw a line which is perpendicular to the given chord, then it becomes two equal right triangles and that line will bisect the angle of circular sector. In this case, there are two 30° - 60° right triangles. Hence, the area of circular segment is
 
 
 
where θ is the angle of circular section in radians (a unit less value of angle). Substitute the values, we have
 
 
 
 
 
The area of a circle is




Therefore, the area of shaded region is




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