Category: Chemical Engineering Math
"Published in Vacaville, California, USA"
Calculate the percentage of MnO2 in a 500 mg sample which after the addition of 80.00 mL of 0.1056 M FeSO4 solution required 8.50 mL of 0.0867 M K2Cr2O7?
Solution:
The given word problem is about oxidation reduction reaction or redox in short. A given sample consists of the mixture of impurities and MnO2. FeSO4 solution is used to titrate MnO2 sample and K2Cr2O7 is used for back up titration. Sulfuric acid is added as a catalyst as follows
For back up titration, K2Cr2O7 solution is used to titrate excess FeSO4 solution as follows
The amount of FeSO4 used to titrate MnO2 is
Hence, the weight of MnO2 in a sample is
Therefore, the weight percent of MnO2 in a sample is
Category: Chemical Engineering Math
"Published in Newark, California, USA"
What is the molarity of a KMnO4 solution standardized against 1.356 gram Na2C2O4 (134 g/mole) requiring 25.1 mL of the solution in acidic medium.
Solution:
The given word problem is about oxidation reduction reaction or redox in short. There's a change of their oxidation numbers in the redox reaction and sulfuric acid is used as a catalyst as follows
Therefore, from the chemical reaction above, the molarity of KMnO4 solution is
Category: Chemical Engineering Math
"Published in Newark, California, USA"
What volume of 0.0305 M EDTA is needed to titrate the Ca in 178.56 mg of CaCO3?
Solution:
If CaCO3 sample is titrated with EDTA disodium salt solution, then the chemical reaction is
Therefore, from the chemical reaction above, the volume of EDTA disodium salt solution to titrate CaCO3 sample is
