Category: Algebra
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Perform the indicated operations
Solution:
Consider the given equation above
The
first thing that we have to do is to examine the radicals first if they can
simplify or not. As a rule in Mathematics, all radicals must be
simplified as much as we can.
At the first term, 16 is not a perfect cube. The factors of 16 are 8 and 2. 8 is a perfect cube.
At the second term, the denominator contains a radical. We need to eliminate the radical sign at the denominator by rationalization of the denominator. Multiply both the numerator and denominator by x2 so that the denominator becomes a perfect cube which is x3.
At the third term, the denominator contains a radical also. We need to eliminate the radical sign at the denominator by rationalization of the denominator. Multiply both the numerator and denominator by 2 so that the denominator becomes a perfect cube which is 8.
Hence, the given equation above becomes
Take the cube root of the numbers inside the radicals that are perfect cube, we have
Since all the terms inside the radicals are the same, then we can combine them and therefore, the final answer is