Free counters!

Monday, May 26, 2014

Finding Missing Digit - Divisibility Rule, 3

Category: Arithmetic

"Published in Newark, California, USA"

Find the missing digit so that it becomes divisible by 4 for

a. 5?627
b. 6721?

Solution:

a. Consider the given number 


Since the last two digit of a given number which is 27 is not a multiple of 4, then the given number is not divisible by 4. There's nothing that we can do in order to become divisible by 4 since the last digit of a given number is not a multiple of 4. You can assign any number to the missing digit but still, the given number will never become divisible by 4.  

b. Consider the given number


A number is divisible by 4 if the last two digit is a multiple of 4. Since 1 is located at the second to the last digit, then we can assign 2 and 6 to the last digit so that 1 becomes 12 and 16 which are the multiples of 4. Therefore, the possible numbers are 67212 and 67216