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Saturday, May 11, 2013

Proving - Parallel Lines, 2

Category: Plane Geometry

"Published in Newark, California, USA"

Given: In ∆ABC, D is the midpoint of AC; DF bisects BDC and ED bisects ADB.

Prove: EF ║ AC


Photo by Math Principles in Everyday Life

Solution:

Consider the given figure and we will label further as follows


Photo by Math Principles in Everyday Life

Proof:

1. Statement: D is the midpoint of line AC.

    Reason: Given item

2. Statement: ED bisects ∠ADB and DF bisects BDC.

    Reason: Given items

3. Statement: ∠ADE ≅ ∠EDB and ∠CDF ≅ ∠FDB.

    Reason: Two bisected angles are congruent to each other.

4. Statement: ∠ADE + ∠EDB + ∠BDF + ∠FDC = 180°

    Reason: The sum of the angles of a straight line is always equal to 180°.

5. Statement: ∠EDB and ∠BDF are complementary angles.

    Reason: From the equation of Statement #4,

               ∠ADE + ∠EDB + ∠BDF + ∠FDC = 180°

    but ∠ADE ≅ ∠EDB and ∠CDF ≅ ∠FDB

    then the above equation becomes

                         2∠EDB + 2∠BDF = 180°

                         2(∠EDB + ∠BDF) = 180°

                             ∠EDB + ∠BDF = 90°
   
6. Statement: ∆EDF is a right triangle.

    Reason: ∠EDF is equal to 90°. ∠EDB and ∠BDF are complementary angles.

7. Statement: EF is the hypotenuse of a rt∆EDF.

    Reason: EF is the opposite side of a right angle of a right triangle. EF is the longest side of a right triangle.

8. Statement: EO ≅ OF

    Reason: If BD is a line bisector of line AC, D is the midpoint of line AC, and D is also a vertex of a rt∆EDF which is a right angle, then line EF which is the hypotenuse of a right triangle will be bisected into EO and OF.

9. Statement: ∆EDO and ∆DOF are isosceles triangles.

    Reason: If BD is a line bisector that passes through the midpoint of the hypotenuse and a vertex of a right triangle which is the opposite angle of the hypotenuse, then BD will bisect a right triangle into two isosceles triangles.

10. Statement: EO ≅ OD and OD ≅ OF.

      Reason: The two sides of an isosceles triangle are congruent.

11. Statement: ∠OED ≅ ∠ODE and ∠ODF ≅ ∠OFD.

      Reason: The two base angles of an isosceles triangles are congruent.

12. Statement: If ∠OED ≅ ∠ODE and ∠ODE ≅ ∠ADE, then ∠OED ≅ ∠ADE.

      Reason: Transitive property of congruence.

13. Statement: If ∠OFD ≅ ∠ODF and ∠ODF ≅ ∠CDF, then ∠OFD ≅ ∠CDF.

      Reason: Transitive property of congruence.

14. Statement: EF ║ AC

      Reason: If the alternating interior angles of a transversal line are congruent, then the two lines that are adjacent to the interior angles are parallel to each other. In the first case, line ED is the transversal line and ∠FED and ∠ADE are the alternating interior angles while in the second case, line DF is the transversal line and ∠EFD and ∠FDC are the alternating interior angles.


Friday, May 10, 2013

Proving - Parallel Lines

Category: Plane Geometry

"Published in Newark, California, USA"

Given: AB ║CD; AF ║EC

Prove: ∠BAF ≅ ∠ECD


Photo by Math Principles in Everyday Life

Solution:

Consider the given figure and we will label further as follows


Photo by Math Principles in Everyday Life

Proof:

1. Statement: AB ║CD; AF ║EC

    Reason: Given items

2. Statement: Draw a line from point A to point C.

    Reason: Line AC will be used as a transversal line.

3. Statement: ∠FAC ≅ ∠ACE

    Reason: If a transversal line AC passes through the parallel lines AF and CE, then their alternating interior angles are congruent.

4. Statement: ∠BAC ≅ ∠ACD

    Reason: If a transversal line AC passes through the parallel lines AB and CD, then their alternating interior angles are congruent.

5. Statement: m∠BAF = m∠BAC - m∠FAC
                      m∠ECD = m∠ACD - m∠ACE

    Reason: Subtraction properties of angles

6. Statement: ∠BAF ≅ ∠ECD

    Reasons: If ∠BAC ≅ ∠ACD and ∠FAC ≅ ∠ACE, then it follows that ∠BAF ≅ ∠ECD.


Thursday, May 9, 2013

Spherical Zone Problems

Category: Solid Geometry, Algebra

"Published in Newark, California, USA"

Show that the area of a zone of one base is equal to the area of the circle whose radius is the chord c of the generating arc AB of the zone. 


Photo by Math Principles in Everyday Life

Solution:

A spherical zone or zone, in short is a portion of the surface of a sphere from its circular cross section to its end (for one base) or between two parallel circular planes (for two bases).  The above figure is a zone of one base.

In this problem, we will compare the area of a zone with the area of a circle whose radius is chord AB or c. Let's see if they will be equal or not. Analyze and label further the given figure above as follows



Photo by Math Principles in Everyday Life

Apply Pythagorean Theorem for ∆OCB,













Apply Pythagorean Theorem for ∆ABC,



The area of a Zone is equal to







The area of a circle whose radius is chord AB or c is equal to





Therefore,

                                       Area of Zone = Area of Circle