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Saturday, October 19, 2013

Special Products - Factoring, 8

Category: Algebra

"Published in Newark, California, USA"

Find the factors completely for


Solution:

Consider the given equation above


Take out their common factor, we have








Since the two grouped terms are the difference of two squares, then we need to factor the two grouped terms as follows



Therefore, the factors are



Friday, October 18, 2013

Special Products - Factoring, 7

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


The first and the last terms are both perfect squares. The middle term is twice the product of the square roots of first and last terms. Let's check the middle term as follows


Since the middle term is exactly the same as the computation above, then the given trinomial is a perfect trinomial square. If the middle term is negative, then the square root of the last term must be negative. Therefore, the factors are



Thursday, October 17, 2013

Special Products - Factoring, 6

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


We can rewrite the above equation as


Since each term is a perfect square and the other term is negative, then the given binomial can be factored by the difference of two squares. Therefore, the factors are



The middle term that contains xc will be equal to zero.