Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
If you will examine the given equation, each terms are perfect cube. (a + b) is considered as a single variable. The given equation can be factored by the sum and difference of two cubes. Therefore, the factors are

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Saturday, October 26, 2013
Friday, October 25, 2013
Special Products - Factoring, 14
Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
If you will examine the equation above, there's a common factor which is a. Take out their common factor as follows
Since each terms in the parenthesis are perfect cube, then we can factor the grouped terms as the sum and difference of two cubes. Therefore, the factors are
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
If you will examine the equation above, there's a common factor which is a. Take out their common factor as follows
Since each terms in the parenthesis are perfect cube, then we can factor the grouped terms as the sum and difference of two cubes. Therefore, the factors are
Thursday, October 24, 2013
Special Products - Factoring, 13
Category: Algebra
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
The given equation has two variables, x and (a + 3b). (a + 3b) is considered as a single variable. It is not a perfect trinomial square because the first and last terms are not perfect square. We can check the above equation using discriminant if it can be factored or not as follows
where a, b, and c are the coefficients of a trinomial. Now, let's check the given equation as follows
Since the value of discriminant is a whole number, then the given equation can be factored. Next, we have to think the factors of the first and last terms so that when we add the product of two factors of the first and last terms, it will be the same as the middle term. The factors of the first term are 1, 12, 2, 6, 3, and 4. The factors of the last term are 1, 15, 3, and 5. Since the last term is negative, then one of the two factors must be negative. We need to do the trial and error in assigning the factors as follows:
Trial 1: Use 1 and 12 for the first term and 1 and -15 for the last term.
The middle term is (1)(-15) + (1)(12) = -15 + 12 = -3.
Trial 2: Use 2 and 6 for the first term and 3 and -5 for the last term.
The middle term is (2)(-5) + (3)(6) = -10 + 18 = 8.
Trial 3: Use 4 and 3 for the first term and 3 and -5 for the last term.
The middle term is (4)(-5) + (3)(3) = -20 + 9 = -11.
Since the middle term is -11x(a + 3b) which is exactly the same as the answer above, then the factors of the given equation are
"Published in Newark, California, USA"
Find the factors for
Solution:
Consider the given equation above
The given equation has two variables, x and (a + 3b). (a + 3b) is considered as a single variable. It is not a perfect trinomial square because the first and last terms are not perfect square. We can check the above equation using discriminant if it can be factored or not as follows
where a, b, and c are the coefficients of a trinomial. Now, let's check the given equation as follows
Since the value of discriminant is a whole number, then the given equation can be factored. Next, we have to think the factors of the first and last terms so that when we add the product of two factors of the first and last terms, it will be the same as the middle term. The factors of the first term are 1, 12, 2, 6, 3, and 4. The factors of the last term are 1, 15, 3, and 5. Since the last term is negative, then one of the two factors must be negative. We need to do the trial and error in assigning the factors as follows:
Trial 1: Use 1 and 12 for the first term and 1 and -15 for the last term.
The middle term is (1)(-15) + (1)(12) = -15 + 12 = -3.
Trial 2: Use 2 and 6 for the first term and 3 and -5 for the last term.
The middle term is (2)(-5) + (3)(6) = -10 + 18 = 8.
Trial 3: Use 4 and 3 for the first term and 3 and -5 for the last term.
The middle term is (4)(-5) + (3)(3) = -20 + 9 = -11.
Since the middle term is -11x(a + 3b) which is exactly the same as the answer above, then the factors of the given equation are
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