Free counters!

Friday, October 25, 2013

Special Products - Factoring, 14

Category: Algebra

"Published in Newark, California, USA"

Find the factors for


Solution:

Consider the given equation above


If you will examine the equation above, there's a common factor which is a. Take out their common factor as follows



Since each terms in the parenthesis are perfect cube, then we can factor the grouped terms as the sum and difference of two cubes. Therefore, the factors are