Category: Integral Calculus, Algebra
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the integral of the given function, we have
The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have
Therefore,

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Wednesday, March 12, 2014
Tuesday, March 11, 2014
Integration - Algebraic Functions, Powers, 21
Category: Integral Calculus, Algebra
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to inspect the terms in the numerator and the denominator if they can factor or not. Did you notice that the numerator can be factored by the difference of two cubes? Let's factor the numerator as follows
Therefore,
where C is the constant of integration.
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to inspect the terms in the numerator and the denominator if they can factor or not. Did you notice that the numerator can be factored by the difference of two cubes? Let's factor the numerator as follows
Therefore,
where C is the constant of integration.
Monday, March 10, 2014
Integration - Algebraic Functions, Powers, 20
Category: Integral Calculus, Algebra
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we need to do is to square the binomial and then apply the distributive property of multiplication over addition, we have
Therefore,
where C is the constant of integration.
"Published in Newark, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we need to do is to square the binomial and then apply the distributive property of multiplication over addition, we have
Therefore,
where C is the constant of integration.
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