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Tuesday, March 11, 2014

Integration - Algebraic Functions, Powers, 21

Category: Integral Calculus, Algebra

"Published in Newark, California, USA"

Evaluate


Solution:

Consider the given equation above


The first thing that we have to do is to inspect the terms in the numerator and the denominator if they can factor or not. Did you notice that the numerator can be factored by the difference of two cubes? Let's factor the numerator as follows







Therefore,


where C is the constant of integration.