Category: Integral Calculus, Algebra
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to square the binomial, we have
Next, integrate the resulting equation, we have
The
constant of integration is not included in the definite integral.
Substitute the values of upper and lower limits to the above equation,
we have
Therefore,

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Saturday, March 15, 2014
Friday, March 14, 2014
Definite Integral - Algebraic Functions, Powers, 3
Category: Integral Calculus, Algebra
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the integral of the given equation, we have
The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have
Therefore,
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the integral of the given equation, we have
The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have
Therefore,
Thursday, March 13, 2014
Definite Integral - Algebraic Functions, Powers, 2
Category: Integral Calculus, Algebra
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the product of two functions, we have
Next, get the integral of the resulting equation above, we have
The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have
Therefore,
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the product of two functions, we have
Next, get the integral of the resulting equation above, we have
The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have
Therefore,
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