Category: Integral Calculus, Algebra
"Published in Vacaville, California, USA"
Evaluate
Solution:
Consider the given equation above
The first thing that we have to do is to get the product of two functions, we have
Next, get the integral of the resulting equation above, we have
The
constant of integration is not included in the definite integral.
Substitute the values of upper and lower limits to the above equation,
we have
Therefore,