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Thursday, March 13, 2014

Definite Integral - Algebraic Functions, Powers, 2

Category: Integral Calculus, Algebra

"Published in Vacaville, California, USA"

Evaluate


Solution:

Consider the given equation above


The first thing that we have to do is to get the product of two functions, we have




Next, get the integral of the resulting equation above, we have




The constant of integration is not included in the definite integral. Substitute the values of upper and lower limits to the above equation, we have











Therefore,